Review Test for Chapters 8 and 9
Hello Math Class! This post provides a review for your upcoming test covering Chapters 8 and 9. Make sure to review the class notes and work through the practice problems to solidify your understanding of the material. Remember, practice makes perfect!
Key Concepts
- Confidence Intervals: A range of values that, with a certain level of confidence, contains the true population parameter. We often use this to estimate the population mean, $\mu$.
- Hypothesis Testing: A method for testing a claim about a population parameter. This involves setting up a null hypothesis ($H_0$) and an alternative hypothesis ($H_a$), calculating a test statistic, and determining whether to reject the null hypothesis based on a chosen significance level, $\alpha$.
- One-Mean t-Test: Used to perform a hypothesis test for a population mean, $\mu$, when the population standard deviation, $\sigma$, is unknown. The test statistic is calculated as: $$t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}}$$, where $\bar{x}$ is the sample mean, $\mu_0$ is the hypothesized population mean, $s$ is the sample standard deviation, and $n$ is the sample size. The degrees of freedom (df) are $n-1$.
Practice Problems (Examples from Class Notes)
Here are some example problems similar to what you might see on the test. Remember to show your work!
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Political Prisoners:
A study on political prisoners with chronic PTSD found that the mean duration of imprisonment for 32 patients was 33.4 months. Assuming $\sigma = 42$ months, determine a 95% confidence interval for the mean duration of imprisonment, $\mu$, of all East German political prisoners with chronic PTSD. Interpret your answer in words.
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Bottlenose Dolphins:
A random sample of 50 adult bottlenose dolphins have a mean length of 12.04 ft with a standard deviation of 1.03 ft. Find and interpret a 90% confidence interval for the mean length of all adult bottlenose dolphins.
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Early-Onset Dementia:
A simple random sample of 21 people with early-onset dementia gave a sample mean age at diagnosis of 52.5 years. Assume the population standard deviation is 6.8 years. At the 1% significance level, do the data provide sufficient evidence to conclude that the mean age at diagnosis of all people with early-onset dementia is less than 55 years old?
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Dirt Bikes:
A random sample of 30 dirt bikes have a mean fuel capacity of 1.91 gallons with a standard deviation of 0.74 gallons. At the 10% significance level, do the data provide sufficient evidence to conclude that the mean fuel tank capacity of all dirt bikes is less than 2 gallons?
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Death Rolls:
A sample of 20 alligator death rolls yielded a sample mean angle between the body and head of 49.0 degrees with a sample standard deviation of 10.0 degrees. At the 5% significance level, do the data provide sufficient evidence to conclude that, on average, the angle between the body and head of an alligator during a death roll is greater than 45°?
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Acid Rain and Lake Acidity:
pH levels were measured for 15 high mountain lakes. The sample mean was found to be 6.6 with a sample standard deviation of 0.67. At the 5% significance level, do the data provide sufficient evidence to conclude that, on average, high mountain lakes in the Southern Alps are nonacidic (pH > 6)?
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TV Viewing:
A random sample of 20 people watched an average of 4.760 hours of television per day last year with a standard deviation of 2.297 hours. In 2005, the average was 4.55 hours. At the 10% significance level, do the data provide sufficient evidence to conclude that the amount of television watched per day last year by the average person differed from that in 2005?
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Golf Robots:
A golf club was tested using a robot to hit a ball six times. The total yards each ball traveled were as follows: 180, 187, 181, 182, 185, 181. The sample mean was 182.7 yards and the sample standard deviation was 2.73 yards. At the 5% significance level, do the data provide sufficient evidence to conclude that the club does what the golfer wants (hits the ball more than 180 yards on average)?
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Nursing-Home Costs:
A random sample of 11 nursing homes yielded a sample mean daily cost of $267.6 with a sample standard deviation of $59.05 for a private room. In 2011, the average cost was $239. At the 5% significance level, does this year's average cost for a private room in a nursing home exceeds that in 2011?
Good luck with your test! Remember to review your notes, practice these problems, and come prepared to show what you've learned! You got this!