Section 7.3

Trigonometric Substitution

When algebraic substitution fails on roots like , we turn to the geometry of triangles. Converting to angles often clears the root.

1

The Three Substitutions

When you see a square root of a sum or difference involving , use a trig substitution. The key is to draw the reference triangle so you can convert back to at the end.

Case 1: → Use

Why it works:
So .

Reference Triangle:
  • (Opp/Hyp)
  • (Adj/Hyp)
θ√(a² - x²)xa

Case 2: → Use

Why it works:
So .

Reference Triangle:
  • (Opp/Adj)
  • (Hyp/Adj)
θax√(a² + x²)

Case 3: → Use

Why it works:
So .

Reference Triangle:
  • (Hyp/Adj)
  • (Opp/Adj)
θa√(x² - a²)x

The Reference Triangle

Mapping x to Theta

Use SOH CAH TOA to find conversions back to x.
2

Worked Example: Circle Area

Case 1: Sine Substitution

Evaluate .

1. Identify the Case

We see with . Use Case 1: .

2. Substitute and Simplify

3. Integrate in θ

Use half-angle:

4. Use Triangle to Return to x

Draw the reference triangle: Since , we have:

  • • Opposite =
  • • Hypotenuse =
  • • Adjacent = (Pythagorean)

Reading from triangle:

θ√(9 - x²)x3
5. Final Answer

3

Level Up Examples

Example A: Case 2 (Tangent)

Evaluate .

1. Identify

See with . Use Case 2: .

2. Substitute

3. Integrate
4. Use Triangle to Return to x

Since :

  • • Opposite =
  • • Adjacent =
  • • Hypotenuse =

Read:

θ4x√(x²+16)
5. Final Answer

Example B: Case 3 (Secant)

Evaluate .

1. Identify

See with . Use Case 3: .

2. Substitute

3. Integrate

4. Use Triangle to Return to x

Since :

  • • Hypotenuse =
  • • Adjacent =
  • • Opposite =

Read:

θ5√(x²-25)x
5. Final Answer

Example C: Completing the Square First

Evaluate .

1. Complete the Square

Now it's form with , .

2. Substitute

3. Integrate
4. Use Triangle to Return to x

Since :

  • • Opposite =
  • • Hypotenuse =

So:

θ√(4-(x-2)²)x-22
5. Final Answer

Example D: Definite Integral

Evaluate .

1. Identify

See . This is , so .

Use:

2. Substitute

3. Integrate


Let :

4. Use Triangle & Change Bounds

Since :

From triangle:

θ32x√(4x²+9)
5. Evaluate

Example E: x in Numerator

Evaluate .

1. Complete the Square

Now with , .

2. Substitute

3. Integrate

4. Use Triangle to Return to x

Since :

  • • Opposite =
  • • Hypotenuse =
  • • Adjacent =

Read:

θ√(3-2x-x²)x+12
5. Final Answer

5

Practice Quiz

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