Angles Formed by Secants & Tangents
When two secants, two tangents, or a secant and tangent meet outside a circle, the angle equals half the difference of the intercepted arcs.
Introduction
This lesson completes the angle-arc trilogy: Central = arc, Inscribed = ½ arc, Outside = ½(big arc − small arc).
Past Knowledge
Inscribed angles (10.1.4). Chord angles (10.2.2). Tangent properties (10.2.1).
Today's Goal
Apply the “half the difference” formula for exterior angles.
Future Success
Segment lengths (10.2.4–10.2.5), coordinate circles (10.3).
Key Concepts
Outside Angle Formula
When vertex is outside the circle (two secants, two tangents, or secant + tangent):
The Complete Angle-Arc Summary
| Vertex Location | Formula |
|---|---|
| At center | angle = arc |
| On circle | angle = ½ arc |
| Inside circle | angle = ½(arc₁ + arc₂) |
| Outside circle | angle = ½(far − near) |
Tangent-Chord Angle (Special Case)
When a tangent and a chord meet at the point of tangency, the angle = ½ intercepted arc (same as inscribed angle).
Worked Examples
Two Secants
Two secants from an external point intercept arcs of 120° (far) and 40° (near). Find the angle.
40°
Secant-Tangent
A secant and tangent from point P. Far arc = 170°, near arc = 50°. Find ∠P.
60°
Two Tangents
Two tangents from P form a 70° angle. Find the minor and major arcs.
Let minor arc = x, major arc = 360 − x.
→
Minor = 110°, Major = 250°.
Minor = 110°, Major = 250°
Common Pitfalls
Sum vs. Difference
Inside = ½(sum). Outside = ½(difference). The most common mistake is using the wrong one. Remember: outside is always smaller, so you subtract.
Far Minus Near (Not Vice Versa)
Always subtract the smaller (nearer) arc from the larger (farther) arc. The result should be positive.
Real-Life Applications
Astronomy — Viewing Angles
When observing a planet from Earth, the angular size depends on the arcs subtended. The secant-tangent relationship helps astronomers calculate apparent sizes.
Security Cameras
A security camera outside a circular building uses the secant-tangent formula to calculate the visible arc of the building's perimeter from its mounting position.
Practice Quiz
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